10n+15n^2=0

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Solution for 10n+15n^2=0 equation: 



10n+15n^2=0

a = 15; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·15·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*15}=\frac{-20}{30}
=-2/3
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*15}=\frac{0}{30}
=0
$

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